=3[4y-2(x+3)+(2-y)]

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Solution for =3[4y-2(x+3)+(2-y)] equation:


Simplifying
0 = 3[4y + -2(x + 3) + (2 + -1y)]

Reorder the terms:
0 = 3[4y + -2(3 + x) + (2 + -1y)]
0 = 3[4y + (3 * -2 + x * -2) + (2 + -1y)]
0 = 3[4y + (-6 + -2x) + (2 + -1y)]

Remove parenthesis around (2 + -1y)
0 = 3[4y + -6 + -2x + 2 + -1y]

Reorder the terms:
0 = 3[-6 + 2 + -2x + 4y + -1y]

Combine like terms: -6 + 2 = -4
0 = 3[-4 + -2x + 4y + -1y]

Combine like terms: 4y + -1y = 3y
0 = 3[-4 + -2x + 3y]
0 = [-4 * 3 + -2x * 3 + 3y * 3]
0 = [-12 + -6x + 9y]

Solving
0 = -12 + -6x + 9y

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '6x' to each side of the equation.
0 + 6x = -12 + -6x + 6x + 9y
Remove the zero:
6x = -12 + -6x + 6x + 9y

Combine like terms: -6x + 6x = 0
6x = -12 + 0 + 9y
6x = -12 + 9y

Divide each side by '6'.
x = -2 + 1.5y

Simplifying
x = -2 + 1.5y

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